How many grams of tin(II) fluoride can be made from 62.5 g of hydrofluoric acid if there is plenty of tin? Â

How many grams of tin(II) fluoride can be made from 62.5 g of hydrofluoric acid if there is plenty of tin?  

answers 0:Tin (II) fluoride is added to some dental products to help prevent tooth decay. Manufacturers have to make the tin (II) fluoride first by reacting tin metal with hydrofluoric acid producing both tin (II) fluoride and hydrogen gas.How many grams of tin(II) fluoride can be made from 62.5 g of hydrofluoric acid if there is plenty of tin available to react?answers 1:Tin(II) Flouride: SnF2; molecular weight = 156.71 g/molHydrofluoric acid: HF; molecular weight = 20.006 g/molMoles of HF: (62.5 g)/(20.006 g/mol) = 3.12 mol HF = 3.12 mol F-Because there are two moles of F- needed per mole of SnF2, 1.56 moles of SnF2 will be formed: (3.12 mol F-)[(1 mol SnF2)/(2 mol F-)] = 1.56 mol SnF2. Therefore, (1.56 mol SnF2)*! (156.71 g/mol) = 244.5 g SnF2 will be formed....